2 years ago

Quadrilateral abcd a(-9-6), B(-4-6), c(-3-2), and D(-8-2)

Mathematics

1 answer:

Katen [24]2 years ago

7 0

Step-by-step explanation:

this is the answer

the quadrilateral thus formed is parallelogram

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Which equation describes the circle having center point (3,7) and the radius r=4 in Standard form

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The equation of circle in standard form is $(x - 3)^2 + (y - 7)^2 = 16$

<h3><u>Solution:</u></h3>

Given that circle having center point (3,7) and the radius r = 4

To find: equation of circle in standard form

<em><u>The equation of circle is given as:</u></em>

$(x - h)^2 + (y - k)^2 = r^2$

Where center (h,k) and radius r units

Given that center point (h , k) = (3, 7) and radius r = 4 units

Substituting the values in above equation of circle,

$(x - 3)^2 + (y - 7)^2 = 4^2\\\\(x - 3)^2 + (y - 7)^2 = 16$

Thus the equation of circle in standard form is $(x - 3)^2 + (y - 7)^2 = 16$

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Step-by-step explanation:

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