Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.
Answer:
add one please i wanna help!
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
Answer:
5v2 – 125 = 0
5(v2−25)=0
v2−25=0
a couple more steps and the answer is...
v=-5
Answer:

Step-by-step explanation:
The standard equation for a circle is given by:

Where (h, k) is the center and r is the radius.
We know that the center is (-4, 8). So, substitute -4 for h and 8 for k:

Simplify:

Now, we will need to find r.
We know that it passes through the point (-2, -1). So, we can substitute -2 for x and -1 for y and solve for r. So:

Evaluate:

Square:

Add:

So, r squared is 85.
We don’t actually have to solve for r itself, since we will have to square it anyways.
So, we have:

Substituting 85 for r squared, we get:

And we have our equation.