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Daniel [21]
3 years ago
15

28 more than a number ?

Mathematics
1 answer:
siniylev [52]3 years ago
4 0

Answer:

28 + x

Step-by-step explanation:

To write this as an expression, you need to find out what sign you need to use ( multiplication, division,etc.)

More than means to add so you are using an addition sign. Now you need a variable to represent the number.

You can pick any letter but for this I am using x. When you put that all together you get the expression, 28 + x.

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Three less than the product of 9 and a number is equal to 6
Alchen [17]

Answer:

3<9n=6 or 3-9n≤6

Step-by-step explanation:

if you are writing an equation I would go with the second

8 0
4 years ago
Read 2 more answers
I need help with this
fomenos

Answer:

B

Step-by-step explanation:

It's B

3^5 = 243

so the 5th root of 243 is 3

(x^7)^(1/5) = x^(7/5)

(y^10)^(1/5) = 7 ^(10/5) = 7^2

z^(21)^(1/5) = z^(21/5)

5 0
3 years ago
Transformation of parent Functions I need help
andrey2020 [161]

Answer:

D: ∛(¼(x + 5))

Step-by-step explanation:

The parent function is;

f(x) = ∛x

A horizontal stretch multiplying by ¼ means that our function is now;

f(x/4) = ∛(x/4)

Now shifting to the left by 5 units denotes;

f(x + 5) = ∛((x + 5)/4)

Or expressed as; ∛(¼(x + 5))

7 0
3 years ago
A 172 ft. building casts a 444 ft. shadow from the sun. To the nearest tenth of a degree, what is the angle of depression? Help
Simora [160]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
An exponential function is given by the equation y=3x. Using the points xx and x+1x+1, show that the y-values increase by a fact
Kobotan [32]

Answer:

Here we have the function:

y = f(x) = 3^x

Using the values:

x and (x + 1)

We need to find that the y-value increases by a factor of 3.

So we need to prove that:

f(x + 1) = 3*f(x).

Or we can see the quotient:

f(x + 1)/f(x) = 3

Here we can find the values:

f(x + 1) = y = 3^(x + 1)

f(x) = y' = 3^x

If we take the quotient, we get:

\frac{f(x + 1)}{f(x)}  = \frac{3^{x + 1}}{3^x}

Here we can use the properties:

a^n*a^m = a^{n + m}

\frac{a^n}{a^m}  = a^{n - m}

Using these in the quotient equation we get:

\frac{f(x + 1)}{f(x)}  = \frac{3^{x + 1}}{3^x} = \frac{3^x*3^1}{3^x} = \frac{3^x}{3^x}*3 = 1*3 = 3

Then:

\frac{f(x + 1)}{f(x)} = 3

f(x + 1) = 3*f(x)

So we found that the y-value increases by a factor of 3 between any two points x₂ and x₁ such that: x₂ - x₁ = 1.

3 0
4 years ago
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