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Fynjy0 [20]
3 years ago
15

N employee earns $175 for 15 hours work. assuming he is paid by the hour, how much will this employee earn in 18 hours?

Mathematics
1 answer:
alekssr [168]3 years ago
7 0
First you would divide 175 by 15 and get 11.6666666667, you would then multiply that by 18 amd get 210.0000000001
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deandre downloaded 8 apps onto his tablet in 12 secs at this rate how many apps could he download in one minute
Misha Larkins [42]

Because 1 minute is 60 seconds, and it takes 12 seconds to download 8 apps, the first thing we need to do is find out how many "sets" of 12 seconds can go in 60 seconds:

60 / 12 = 5

Now, all we have to do is multiply the number of apps by 5, and we get our answer:

8 · 5 = 40

So, it would take Deandre 1 minute to download 40 apps.

7 0
3 years ago
Suppose that Y varies directly with X, and Y = 4 when X = 16
mylen [45]

Answer:

find k first

y=kx

4=k16

k=0.25

then find y

y=kx

y=0.25x3

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3 years ago
Simplify the question above
andrey2020 [161]

Answer:

1 +  \frac{3}{x}

Step-by-step explanation:

1) Rewrite x² - 9 in the form a² - b² where, a = x and b = 3.

\frac{ {x}^{2} -  {3}^{2}  }{ {x}^{2}  - 3x}

2) use difference of squares: a² - b² = ( a + b ) (a - b).

\frac{(x + 3)(x - 3)}{ {x}^{2}  - 3x}

3) Factor out the common term x.

\frac{(x + 3)(x - 3)}{ x(x  - 3)}

4) Cancle out x - 3 .

\frac{x + 3}{x}

5) Simplify.

1 +  \frac{3}{x}

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>1</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>3</u></em><em><u>/</u></em><em><u>x</u></em><em><u>.</u></em>

6 0
3 years ago
Read 2 more answers
Help its urgent!! I can not figure it out!!
gladu [14]
What is the problem?
5 0
4 years ago
Set Question involving real and natural numbers
Allushta [10]

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(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}

√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then

(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}

A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that

(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}

I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then

(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.

N is a subset of B, so

(iv.b) N - B = N = {1, 2, 3, ...}

3 0
3 years ago
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