Question

Find the area of the entire figure.

Answer 1

Answer:

$\large\boxed{A=171.555\ in^2}$

Step-by-step explanation:

We have the right triangle and the trapezoid.

The formula of an area of a right triangle:

$A_{triangle}=\dfrac{ab}{2}$

a, b - legs

We have the length of the legs 12in and 13.42 in. Substitute:

$A_{triangle}=\dfrac{(12)(13.42)}{2}=80.52\ in^2$

The formula of an area of a trapezoid:

$A_{trapezoid}=\dfrac{(b_1+b_2)h}{2}$

b₁, b₂ - bases

h - height

We have the length of the bases 18in and 11.75in and the length of the height 6.12in. Substitute:

$A_{trapezoid}=\dfrac{(18+11.75)(6.12)}{2}=\dfrac{(29.75)(6.12)}{2}=91.035\ in^2$

The area of the figure:

$A=A_{triangle}+A_{trapezoid}$

Substitute:

$A=80.52+91.035=171.555\ in^2$