Answer:
Initial amount P = $12000
Interest after 2 years I = 4%*2 = 8%
<u>Investment into Trust fund:</u>
- $12000 + $5000 + 0.08*$12000 = $17960
<u>Interest amount to exceed $20000:</u>
<u>Time required to get $2040:</u>
- 17960*0.045x = 2040
- 808.2x = 2040
- x = 2040/808.2
- x = 2.52 years
The investment will exceed $20000 in the second half of the third year
Answer:

Step-by-step explanation:
1) Add 1 to both sides.

2) Simplify -3 + 1 to -2.

3) Multiply both sides by 6.

4) Simplify 2 × 6 to 12.

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>h</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-12</u></em><em><u>.</u></em>
The time × 1.5=the distance
so 5×1.5=7.5
10×1.5=15
20×1.5=30
im a 7th grader doing 8th grade math.. just think
Given AP is 21 ,18,15,...
First term = 21
Common difference = 18-21 = -3
Let an = -81
We know that
an = a+(n-1)d
⇛21+(n-1)(-3) = -81
⇛ 21-3n+3 = -81
⇛24-3n = -81
⇛ 24+81 = 3n
⇛ 105= 3n
⇛ n = 105/3
⇛ n = 35
35th term of the AP is -81.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> Which term of a AP 5 , 13 , 21 ,... is 181?
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Which term of the AP:3, 8, 13, 18,...,is 78?
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