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3 years ago

The axis of symmetry for the graph of the function f(x) =

Mathematics

1 answer:

lara [203]3 years ago

7 0

Answer:

Step-by-step explanation:

$y = - x {}^{2} + bx + 10 \\ y = - (x {}^{2} - bx - 10) \\ y = -( (x - \frac{b}{2} ) {}^{2} - \frac{b {}^{2} }{4} - 10) \\ y = - (x - \frac{b}{2} ) {}^{2} + 10 + \frac{b {}^{2} }{4} \\ \\ therefore \: \frac{b}{2} = 6 \\ b = 12$

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Please help your sis out!!!!!!!!!!

spayn [35]

You would input 10 as m into the equation
t= 0.05(10) +60
t=0.5+60
t=60.5

7 0

3 years ago

Read 2 more answers

Express 6 3/4 in simplest radical form

Hoochie [10]

Answer:

4√6^3

Step-by-step explanation:

3 0

3 years ago

Draw the graph of the line that is perpendicular to Y= 4X +1 and goes through the point (2, 3)

spayn [35]

Given:

$\begin{gathered} y=4x+1 \\ \text{ point }(2,3) \end{gathered}$

To find:

Draw a graph of a line that is perpendicular to the given line and passing through a given point.

Explanation:

As we know that relation between two slopes of perpendicular slopes of lines:

$m_1.m_2=-1$

Slope of given line y = 4x + 1 is:

$m_2=4$

So, the slope of line perpendicular to given line is:

$m_2=-\frac{1}{4}$

Also, so line equation that is perpendicular to given line is:

$y=-\frac{1}{4}x+c...........(i)$

Also, the required line is passing thorugh given point (2, 3), i.e.,

$\begin{gathered} 3=-\frac{1}{4}(2)+c \\ c=3+\frac{1}{2} \\ c=\frac{7}{2} \end{gathered}$

So, line equation that is perpendicular to given line is:

$y=-\frac{1}{4}x+\frac{7}{2}$

The required graph of line is:

8 0

2 years ago

The basic price for an annual dental checkup and cleaning is $50. If the dentist finds any cavities in there will be an addition

Slav-nsk [51]

Answer:

100n+50

Step-by-step explanation:

the dentist charges $100 dollars per cavity found. Per indicates multiplication. Since there is an additional fee, we add $50 to the $100n, which will make the expression

$100n+50

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3 years ago

How would you graph the solution set of the system of inequalities {3y≤2x+6} { 2x+y>0}

7nadin3 [17]

1) Solve the first inequality

3y ≤ 2x + 6

=> y ≤ 2x/3 + 2

2) Draw the line y = 2x/3 + 2

3) Shade the region below the line y = 2x/3 + 2

4) Solve the inequality 2x + y > 0

=> y > - 2x

5) draw the line y = -2x

6) Shade the region above the line y = -2x

7) The solution is the region between the two lines shaded including the portion of the line y = 2x/3 + 2

5 0

4 years ago