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3 years ago

You just started working at Chicken Stop Restaurant after school. You earn 10 dollars an hour, and work 20 hours a week.

Mathematics

1 answer:

Katen [24]3 years ago

7 0

Answer:

800 monthly

Step-by-step explanation:10times20=200

4 weeks in a month so you do week1 200,week2 400,week3 600,week4 800.

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in her last computer game, Lucy scored 3×10⁷ points. The first time she tried the game, she scored 6×10³ points. How many times

ipn [44]

Answer:

u have to drop 18 pionts .

Step-by-step explanation:

5 0

3 years ago

-8= 3-5(x+6) solving algebraicaily

SOVA2 [1]

Let's solve your equation step by step

-8=3-5(x+6)

Step 1: simplify both sides of the equation

-8=3-5(x+6)

-8=3+(-5)(x)+(-5(6) (distribute)

-8=3+-5x+-30

-8=(-5x)+(3+-30) (combine like terms)

-8=-5x+-27

-8=-5x-27

Step 2: flip the equation

-5x-27=-8

Step 3: add 27 to both sides

-5x-27+27=-8+27

-5x=19

Step 4: Divide both sides by -5

-5x/-5 = 19/-5

Answer : x= -19/5

4 0

4 years ago

Read 2 more answers

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is: