Answer:
-502.5 − 115 = -617.5
The submarine’s elevation after its final dive is -617.5 feet, or 617.5 feet below sea level.
Step-by-step explanation:
Plato answer
Nxnxnxbbxnxndnnsnsn nsnsnsndnnsndnndndnsndnndndnndnd
Answer:
![f^{-1} (x)=x^{2} -3](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29%3Dx%5E%7B2%7D%20-3)
Step-by-step explanation:
Given the function
![f\left(x\right)=\sqrt{x+3}](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3D%5Csqrt%7Bx%2B3%7D)
We can find the inverse function by exchanging x and y, and then solve for y.
![y=\sqrt{x+3}](https://tex.z-dn.net/?f=y%3D%5Csqrt%7Bx%2B3%7D)
Replace x with y.
![x=\sqrt{y+3}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7By%2B3%7D)
square both sides
![x^2=y+3](https://tex.z-dn.net/?f=x%5E2%3Dy%2B3)
![y=x^2-3](https://tex.z-dn.net/?f=y%3Dx%5E2-3)
Hence,
![f^{-1} (x)=x^{2} -3](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29%3Dx%5E%7B2%7D%20-3)
Answer:
10000000000000000000000000000000000000000
Step-by-step explanation:
If you are doing 10 to the power of something just write 1 and then the amount of zeros as the power.
So for this question I wrote 1 and the 40 zeros.
Answer:
The width of rectangle is 1 unit.
Step-by-step explanation:
Given:
The area of rectangle is 6 units and its width is 5 units less than the length.
So, to find the width of rectangle.
Let the length be
and the width be
.
Now, to find the width we put the formula of area of rectangle:
Area = length × width
![6= x\times (x-5)](https://tex.z-dn.net/?f=6%3D%20x%5Ctimes%20%28x-5%29)
![6=x^{2}-5x](https://tex.z-dn.net/?f=6%3Dx%5E%7B2%7D-5x)
![0=x^{2}-5x-6](https://tex.z-dn.net/?f=0%3Dx%5E%7B2%7D-5x-6)
![0=x^{2}-6x+x-6](https://tex.z-dn.net/?f=0%3Dx%5E%7B2%7D-6x%2Bx-6)
![0=x(x-6)+1(x-6)](https://tex.z-dn.net/?f=0%3Dx%28x-6%29%2B1%28x-6%29)
![0=(x-6)(x+1)](https://tex.z-dn.net/?f=0%3D%28x-6%29%28x%2B1%29)
<em>On solving equation we get:</em>
![x-6=0, x+1=0](https://tex.z-dn.net/?f=x-6%3D0%2C%20x%2B1%3D0)
Therefore, we take the value x=6 as it is positive value:
![x-6=0](https://tex.z-dn.net/?f=x-6%3D0)
![x=6](https://tex.z-dn.net/?f=x%3D6)
So, the width of rectangle:
Width = ![x-5](https://tex.z-dn.net/?f=x-5)
= ![6-5](https://tex.z-dn.net/?f=6-5)
= ![1](https://tex.z-dn.net/?f=1)
Therefore, the width of rectangle is 1 unit.