Answer:
the answer is 29.1
Step-by-step explanation:
do 30 * .97

40x=356000 x= 8900 applications
you make x the number of total applications
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
a.
Step-by-step explanation:
by elimanation,cimparison or substitution you wull get the value of x=-60/17 and y=6/17
Hello!
3.41 × 8.5 = 28.985
The product of 3.41 and 8.5 is 28.985, which has three decimal places.