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ss7ja [257]
3 years ago
12

Collin's retirement party costs $4 for every guest he invites. What is the maximum number of guests there can be if Collin can a

fford to spend a total of $24 on his retirement party
Mathematics
1 answer:
steposvetlana [31]3 years ago
6 0

Answer:

Collin can invite maximum 6 guest to his retirement party.

Step-by-step explanation:

Total cost of retirement party = $24

Cost to be spend on each guest = $4

Number of guests to be invited in the retirement party= x

x\times \$4=\$24

x=\frac{\$24}{\$4}

x = 6

Collin can invite maximum 6 guest to his retirement party.

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M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
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Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

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      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

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Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

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Therefore the required polynomial is

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3 years ago
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Answer:

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<u>Isosceles trapezoid</u>

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