Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

Question

2 years ago

11

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?
A. `4/11`
B. `7/11`
C. `3/11`
D. `2/3`

Mathematics

1 answer:

pantera1 [17] · Answer 1 · 2022-06-12T05:43:15+03:00

pantera1 [17]2 years ago

4 0

The total flowers is 4 + 3 + 4 = 11

4 roses + 3 carnations = 7

Probability of picking either a rose or a carnation = 7/11