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Nesterboy [21]
3 years ago
11

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?
A. `4/11`
B. `7/11`
C. `3/11`
D. `2/3`
Mathematics
1 answer:
pantera1 [17]3 years ago
4 0

The total flowers is 4 + 3 + 4 = 11

4 roses + 3 carnations = 7

Probability of picking either a rose or a carnation = 7/11

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