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Readme [11.4K]
3 years ago
13

ASAP question in the picture

Mathematics
1 answer:
Scilla [17]3 years ago
6 0

Answer:

try answer C 33ft

Step-by-step explanation:

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first, the slope is needed, which is 3-2/3--3 which is 1/6 and so this will be y=(1/6)x+b which then we'll input (3,3) which is 3=2+b or b=1 so the equation is y=(1/6)x+1

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2 years ago
What is 2 times 3/4 please answer
nalin [4]
The answer is 1.5 or 1 1/2
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Hi, so i have a question and i'm giving away free points so here's the question! If you answer ill put out another question and
Shtirlitz [24]

Answer:

1. Saturday

2(a) 10,944

2(b) 32700

3. (16,24)

Step-by-step explanation:

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3 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
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