What does it mean when is says write a sequence hat plots the ordered pair if you start at the origin when you are plotting ??

1 answer:

6 0

I didn’t quite understand what you were asking, but the origin is (0,0) so you would plot a dot at the origin being (0,0) then depending on your other numbers, you’d plot them using your Y and X

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Find the x-intercepts for the parabola defined by the equation below. y = x2 + 9x + 14

faltersainse [42]

Answer:

x - intercepts are (-7,0) and (-2,0)

A is the correct option.

Step-by-step explanation:

We have been given the equation of the parabola $y=x^2+9x+14$

For x- intercept, y = 0

$0=x^2+9x+14$

We can split the middle term as 9x = 7x +2x

$x^2+7x+2x+14=0$

Now take GCF

$x(x+7)+2(x+7)=0$

Factored out the common term

$(x+7)(x+2)=0$

Apply the zero product property

$(x+7)=0,(x+2)=0$

Solve for x

$x=-7,-2$

Hence, x - intercepts are (-7,0) and (-2,0)

A is the correct option.

4 0

3 years ago

HELP 76 POINTS IF YOU DO Which equations represent linear functions?

asambeis [7]

My answer would be A and D

4 0

2 years ago

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The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented

leva [86]

The equation of the hyperbola is : $\frac{x^{2}}{48^2} - \frac{y^{2}}{14^2} = 1$

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$