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alina1380 [7]
3 years ago
10

What does it mean when is says write a sequence hat plots the ordered pair if you start at the origin when you are plotting ??

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0
I didn’t quite understand what you were asking, but the origin is (0,0) so you would plot a dot at the origin being (0,0) then depending on your other numbers, you’d plot them using your Y and X
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Find the approximate side length of a square game board with an area of 171 in?
Makovka662 [10]

<em>Greetings from Brasil...</em>

According to the statement of the question, we conclude that the area of a square is requested, whose value is 171 in²

The area of a square is given by the expression:

A = S²

<em>where S is the side of the square - just what we want to know</em>

So:

A = S²

171 = S²

√171 = S

<h3>S ≈ 13.08in</h3>
8 0
4 years ago
At a hockey game, a vender sold a combined total of 204 sodas and hot dogs. The number of sodas sold was three times the number
Zielflug [23.3K]

Answer:

Step-by-step explanation:

Given that at a hockey game, a vender sold a combined total of 204 sodas and hot dogs.

The number of sodas sold was three times the number of hot dogs sold.

Let no of hot dogs be sold be x then no of sodas sold will be 3x

Total number of sodas and hot dogs = x+3x=204\\x=51\\3x=153

the number of sodas =153

and the number of hot dogs sold=51

6 0
4 years ago
(2/3-5/6)+(9/4-3/5) simplify
nasty-shy [4]

remove parenthesis : 2/3 - 5/6 + 9/4 - 3/5

add fractions based on lcm : 40/60 - 50/60 + 135/60 - 36/60

equal denominator so combine fractions : 40 - 50 + 135 - 36 / 60

add/subtract : 40 - 50 + 135 - 36 = 89

answer ; 89/60

5 0
3 years ago
Read 2 more answers
The class has 30 boxes of pencils each package each package has 10 pencils the class needs 600 pencils how many more boxes does
serg [7]
The class needs 40 more boxes , I don’t know why they need 600 pencils but they do
7 0
4 years ago
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y&#10;\\\\\\&#10;\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\&#10;-------------------------------\\\\&#10;

\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}&#10;\\\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
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