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MakcuM [25]
2 years ago
11

What is 72/60 in simplest form

Mathematics
2 answers:
Andrew [12]2 years ago
6 0
Okay so we know your problem is 72/60
So, first find out how many times 60 can go into 72
This is 1 so right now we have. 1 12/60 right?
Now this still isn't simplest form so what number can go into bolth 12 and 60?
12 right?
Okay, so 4 x 3 = 12 so now we have 1 3/60
Now lets deal with 60 15 x 4 = 60. now we have 1 3/15
We can still make it smaller so we know 3 can go into 3 and 15 so lets use 3
1 ~ 3 = 1 so we have 1 1 / 15
5 x 3 = 15
So your answer is....

1 1 / 15

Hope This Helped

Cheers,
Belive1234
nexus9112 [7]2 years ago
3 0
You have to divide both by common factor, in this case it's 12
So 72/60 = 6/5
Thus, 6/5 is the simplest form.
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Amelia launched her science fair rocket, and then backed away. The path of the rocket is given by the equation below, where y is
Mamont248 [21]

Answer:

1)The rocket hit the ground at     x = \frac{5}{4}

2)The maximum height of the rocket = 12.468 feet

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  

                y = -2 x² + 5 x + 7 ...(i)

Differentiating equation (i) with respective to 'x' , we get

             \frac{dy}{dx} = -2( 2x) +5(1) =  -4x +5

Equating zero

            \frac{dy}{dx} = 0

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⇒      -4 x = -5

⇒          x = \frac{5}{4}

<em> The rocket hit the ground at     </em>x = \frac{5}{4}<em></em>

<u><em>Step(ii):</em></u>-

    \frac{dy}{dx}  =  -4x +5  ...(ii)

Again differentiating equation (ii) with respective to 'x' , we get

 \frac{d^{2} y}{dx^{2} }  = - 4(1)

The maximum height at x = \frac{-5}{4}

  y = -2 x² + 5 x + 7

 y = -2 (\frac{5}{4})^{2}  + 5 (\frac{5}{4} )  + 7

y = \frac{-2(25)+ 25 (16)+7(64)}{64}

y = \frac{798}{64} = 12.468 feet

<em>The maximum height of the rocket = 12.468 feet</em>

       

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2 years ago
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Deffense [45]

Answer:

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Step-by-step explanation:

Given :-

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The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}

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