Divide 216 into the ratio 1;5

The graph of the piecewise function f(x) is shown.<br> 1 f(x)

Tema [17]

Answer:

In a word processing document or on a separate piece of paper, use the guide to construct a two-column proof proving that lines l and m are parallel.

6 0

3 years ago

What is the quotient?

yuradex [85]

Answer:

-1.58208955224

Step-by-step explanation:

DO THE MATH

5 0

3 years ago

The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from

Vinvika [58]

Answer:

$t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771$

$df=n_1 +n_2 -2=13+19-2=30$

Since is a right tailed test the p value would be:

$p_v =P(t_{30}>1.771)=0.0434$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

$\bar X_{1}=810$ represent the mean for sample 1

$\bar X_{2}=770$ represent the mean for sample 2

$s_{1}=67$ represent the sample standard deviation for 1

$s_{2}=56$ represent the sample standard deviation for 2

$n_{1}=13$ sample size for the group 2

$n_{2}=19$ sample size for the group 2

$\alpha=0.05$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=13+19-2=30$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771$

P value

Since is a right tailed test the p value would be:

$p_v =P(t_{30}>1.771)=0.0434$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

4 0

3 years ago

One truck delivered 3 4/5 tons of potatoes to a warehouse while another truck delivered 1/2 ton less. How many tons of potatoes

Savatey [412]

3 4/5 + (3 4/5 - 1/2) =
19/5 + (19/5 - 1/2) =
19/5 + (38/10 - 5/10) =
19/5 + 33/10 =
38/10 + 33/10 =
71/10 which equals 7 1/10 tons <==

5 0

3 years ago

Read 2 more answers

growth of a particular type of plant. He is testing the effects of four growth factors: lighting, age, temperature, and humidity

GREYUIT [131]

The level of each growth factor is an illustration of a combination

There are 90 ways of combining one level from each growth factors

<h3>How to determine the number of combinations?</h3>

From the complete question (see attachment), we have the number of levels in each growth factor is:

Lighting = 3

Age = 5

Temperature = 2

Humidity = 3

So, the number of combination (n) is:

n = 3 * 5 * 2 * 3

n = 90

Hence, there are 90 ways of combining one level from each growth factor.