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Anna71 [15]
3 years ago
10

Miles is planning to spend 2/3 as many hours bicycling this week as he did last week. Is Miles going to spend more hours or fewe

r hours bicycling this weekind than last week?
Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

Fewer hours

Step-by-step explanation:

2/3 is a fraction and shows the parts of a whole. This means that 2/3 of last week is fewer than last week. Last week is the whole for example 15 hours. This week will be 2/3 or 2/3*15 = 10 hours. This week will be less than last week.

You might be interested in
It took Mary 1.5 hours to bicycle 39km. Then she slowed down and took another 3 hours to bicycle 51 km more. Find her average sp
Goshia [24]
39/1.5 = 26 km per hour
51/3 = 17 km per hour
Then you need the mean. 26+17/2 = 21.5 km per hour
4 0
3 years ago
The measure of the supplement of an angle is 20° more than three times the measure of the original angle. find the measures of t
viva [34]

If the original angle is x degrees then its supplement is 180 - x degrees.

we have the equation:-

180 - x = 3x + 20

160 = 4x

x = 40

The original angle is 40 degrees and its supplement is 140 degrees

3 0
3 years ago
The image of a parabolic lens is traced onto a graph. The function f(x) = (x + 8)(x – 4) represents the image. At which points d
alexandr402 [8]

Answer:

x = -8 and x = 4

Step-by-step explanation:

given

f(x) = (x+8) (x - 4)

recall that at any point on the x-axis, y = 0 [i.e f(x) = 0]

hence to find where the graph crosses the x-axis, we simply substitue f(x) = 0 into the equation and solve for x

f(x) = (x+8) (x - 4)

0 = (x+8) (x - 4)

Hence

either,

(x+8) = 0 ----> x = -8  (first crossing point)

or

(x-4) = 0 ------> x = 4 (second crossing point)

Hence the graph crosses the x-axis at x = -8 and x = 4

7 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
John left the museum and drove south at a rate of 55 mph. Sally left four hours later driving 10 mph faster than John in an effo
Leona [35]

Answer:

22 hours (B)

Step-by-step explanation:

John's velocity = 55mph

Sally's velocity = 65mph

John's time taken = x

Sally's time taken = x - 4

since they must cover the same distance.

and, distance = vel × time

Sally's vel × time = John's vel × time

55x = 65(x-4)

55x = 65x - 220

-10x = -220

x = 22 hours.

Therefore, Sally catches up after 22 hours

5 0
3 years ago
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