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Dimas [21]
3 years ago
5

What is the slope of the line passes through the pair of points (-4.1,7.4), (4.3,3.2)

Mathematics
1 answer:
Paladinen [302]3 years ago
3 0
Hi there! The formula for finding the slope is y2 - y1/ x2 - x1. This means you subtract the first x and y-coordinates form the second x and y-coordinates. (-4.1, 7.4) is the first coordinate and (4.3, 3.2) is the second coordiante. Set it up like this:

3.2 - 7.4 / 4.3 - (-4.1)

Now, let's subtract. 3.2 - 7.4 is -4.2. 4.3 - (-4.1) is 9.4. -4.2/9.4 is -0.5 when simplified. There. The slope of the line is -0.5. The answer is C: -0.5.

Note: When you subtract a negative number, you're actually adding. So if an expression is 2 - (-3), the answer is 5, because you add 3 into 2.
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See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

We need to begin with the definition of tangent:

tan (x) =\frac{sin(x)}{cos(x)}

So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

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If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

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The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

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Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

7 0
3 years ago
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