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Julli [10]
3 years ago
7

Find the volume of the figure below.

Mathematics
2 answers:
Taya2010 [7]3 years ago
8 0
B- the volume of a cone is pi(r^2)(h/3) where r=radius and h= height.
When you plug in r &h you get pi(6^2)(19.6/3) =
pi(36)(6.53)=738.9
dimulka [17.4K]3 years ago
5 0

Answer:

B. \displaystyle 738,9\:units^3

Step-by-step explanation:

\displaystyle πr^2\frac{h}{3} = V \\ \\ π[6]^2[\frac{19,6}{3}] = 36π[\frac{19,6}{3}] = 235\frac{1}{5}π ≈ 738,9025921 ≈ 738,9

* The <em>radius</em> is half the <em>diameter</em>.

I am joyous to assist you anytime.

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What is the range of the function y = x 2?
Leno4ka [110]

Answer:

\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

The graph is also attached below.

Step-by-step explanation:

Given the function

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\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)

\mathrm{If}\:a

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\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

The graph is also attached below.

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