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Sergio039 [100]
2 years ago
12

An animal cage is holding 5 black cats and 8 white cats. None of them want to be in there. The cage door is opened slightly and

two cats escape. What is the probability that one of each color escapes?
Mathematics
1 answer:
nata0808 [166]2 years ago
8 0

Answer:

\[\frac{1}{40}\]

Step-by-step explanation:

The animal cage contains 5 black cats and 8 white cats.

So the probability of 1 out of 5 black cats escaping can be expressed as \[\frac{1}{5}\]

The probability of 1 out of 8 white cats escaping can be expressed as \[\frac{1}{8}\]

The combined probability of 1 black cat and 1 white cat escaping can be expressed as a product of the above two probabilities.

In other words, the combined probability is \[\frac{1}{5} * \frac{1}{8}\]

\[= \frac{1}{40}\]

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<u>Answer: </u>

Expression x + 2my + z represents cost of order where x, y, z are cost of small , medium and large drinks (in dollars) respectively.

<u>Solution: </u>

Given that  

Juan’s family ordered a small drink and m medium drinks.

Alex family ordered m medium drinks and a large drink.

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Let’s assume cost of one small drink = x

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Step-by-step explanation:

You have correctly determined the domain to be from x = -6 to x < -1. In interval notation, that would be ...

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