Pls help with this much apreciated

Help please!!! AHAHSBHSBDR

Degger [83]

Answer:

a = 8/29 thus: Step 1 is wrong!

Step-by-step explanation:

Solve for a:

8 - a/2 = 3 (4 - 5 a)

Hint: | Put the fractions in 8 - a/2 over a common denominator.

Put each term in 8 - a/2 over the common denominator 2: 8 - a/2 = 16/2 - a/2:

16/2 - a/2 = 3 (4 - 5 a)

Hint: | Combine 16/2 - a/2 into a single fraction.

16/2 - a/2 = (16 - a)/2:

(16 - a)/2 = 3 (4 - 5 a)

Hint: | Make (16 - a)/2 = 3 (4 - 5 a) simpler by multiplying both sides by a constant.

Multiply both sides by 2:

(2 (16 - a))/2 = 2×3 (4 - 5 a)

Hint: | Cancel common terms in the numerator and denominator of (2 (16 - a))/2.

(2 (16 - a))/2 = 2/2×(16 - a) = 16 - a:

16 - a = 2×3 (4 - 5 a)

Hint: | Multiply 2 and 3 together.

2×3 = 6:

16 - a = 6 (4 - 5 a)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

16 - a = 24 - 30 a

Hint: | Move terms with a to the left hand side.

Add 30 a to both sides:

30 a - a + 16 = (30 a - 30 a) + 24

Hint: | Look for the difference of two identical terms.

30 a - 30 a = 0:

30 a - a + 16 = 24

Hint: | Group like terms in 30 a - a + 16.

Grouping like terms, 30 a - a + 16 = (-a + 30 a) + 16:

(-a + 30 a) + 16 = 24

Hint: | Combine like terms in 30 a - a.

30 a - a = 29 a:

29 a + 16 = 24

Hint: | Isolate terms with a to the left hand side.

Subtract 16 from both sides:

29 a + (16 - 16) = 24 - 16

Hint: | Look for the difference of two identical terms.

16 - 16 = 0:

29 a = 24 - 16

Hint: | Evaluate 24 - 16.

24 - 16 = 8:

29 a = 8

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 29 a = 8 by 29:

(29 a)/29 = 8/29

Hint: | Any nonzero number divided by itself is one.

29/29 = 1:

Answer: a = 8/29

5 0

3 years ago

Please answer this quickly

tester [92]

Answer:

C. 5x + 11 = 36

Step-by-step explanation:

You can see in the diagram that there are 5 x variables and eleven which make up the total diagram that says 36 so it would have to be 5x+11 = 36

4 0

3 years ago

Read 2 more answers

Write the missing decimal so the each pair adds to 1

oee [108]

Answer:

top one is 0.6 bottom one is 0.1

7 0

3 years ago

50 POINTS & BRAINLIEST!!!! HELP ASAP!!!

Allisa [31]

6(2x - 11) + 15 = 21

First step use distributive property on the left side to remove the parenthesis, to do this multiply 6 by each term inside the parenthesis:

12x - 66 + 15 = 21

Second step, simplify the left side by combining the like terms:

12x - 51 = 21

Third step, add 51 to both sides of the equation:

12x = 72

Last step, divide both sides by 12:

x = 72/12

x = 6

3 0

3 years ago

New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.

elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L) = probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H) = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore, the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0

3 years ago