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aliina [53]
3 years ago
8

Select the correct answer.

English
2 answers:
umka2103 [35]3 years ago
7 0

Answer:

The first step is choosing a topic.

Explanation:

In order, the research process is:

1. Choose a topic

2. Find backround information

3. Drafting and essay

4. Citing sources

Andrew [12]3 years ago
6 0

Answer:

c

Explanation:

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1. Why don't you let me .............that
Lady bird [3.3K]

Answer:

Explanation:

do. You need a present tense ( a simple verb at that)

Did is past

done is also past as in Done meaning completed after it was started a while ago.

to do is an infinitive. You need a simple present tense verb. To go where no man has gone before.

To do what no one has attempted before.

3 0
2 years ago
What is the definition of pun
dem82 [27]

Answer:

a joke exploiting the different possible meanings of a word or the fact that there are words which sound alike but have different meanings.

Explanation:

hope it helps lol

6 0
3 years ago
Read the excerpt from chapter 5 of The Adventures of Huckleberry Finn, in which Huck describes his father. He was most fifty, an
balu736 [363]
The effect of the narrative description of Huck's father is of a man who is not looked after, who is poverty stricken and unkempt and with low self esteem and for example re his hair that was greasy and hung down ie was dirty and not combed shows this. Also, from the sounds of it he was lily white, what we might call someone 'white trash' white these days. 
6 0
2 years ago
Read 2 more answers
I will make you brainlist if you help me the 2 question by explain them i swear i will make you brainlist
Xelga [282]

★ Formula Applied :

\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}

\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}

\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}

\bullet\ \; \sf \ln (ab)=\ln a+\ln

★ Explanation :

\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}

\to \sf \red{-ln|sin2x|+c}

\to \sf - \ln |2sinx.cosx|+c

\to \sf - \ln |sinx.cosx|+(\ln 2+c)

\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar

★ Alternate Method :

\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}

\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx

\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}

\to \sf ln\left| \dfrac{secx}{sinx}\right|+c

\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}]

\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar

4 0
3 years ago
The five w's are important in explicating poetry and writing in a journalistic style
svetoff [14.1K]
What, who,when, where, & why
4 0
3 years ago
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