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MAVERICK [17]
3 years ago
6

PLEASE HELP A store is having a sale on chocolate chips and walnuts. For 5 pounds of chocolate chips and 3 pounds of walnuts, th

e total cost is $21. For 2 pounds of
chocolate chips and 6 pounds of walnuts, the total cost is $24. Find the cost for each pound of chocolate chips and each pound of walnuts.
Mathematics
1 answer:
Stells [14]3 years ago
3 0

Answer:

Chocolate Chips cost $2.25 and Walnuts cost $3.25 per pound each

Step-by-step explanatChocion:

Let x = cost of pounds of chocolate chip cookies and y = cost of pounds of walnuts.

From the question, we get 5x+3y = 21 and 2x+6y = 24. To solve the equation, we use substitution. From the first equation, we get y = (21-5x)/3. We substitute the y into the second equation to get 2x + 6(21-5x)/3 = 24. This turns out to be 2x+(42-10x) = 24. Adding like terms you should get 42-8x = 24. Solving for x, x = $2.25 per pound. Plugging this into the first equation, we get 5(2.25)+3y = 21. Solving for y, we get $3.25 per pound of walnuts. If we plug in the numbers into the 2 equations, we will get the right total.

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Answer:  The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation:  The given system of linear equations is :

2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.

Now, from equations (ii) and (iii), we have

x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.

From equations (iv) and (v), we get

y=\dfrac{11-3}{2}=4,\\\\z=10-3\times3=1.

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

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