50/250 = 1/5 = 0.20 = 20%
Answer: 20%
Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
First multiply the power, 3 x -2 = -6
Thus, 5^-6
Make the power positive
1/5^6
1/15625
Answer:
There are no errors
Step-by-step explanation:
The math is correct
The answer to this question is : <span>Megohm meter</span>