In ΔTUV, the measure of ∠V=90°, the measure of ∠T=72°, and VT = 6.6 feet. Find the length of TU to the nearest tenth of a foot.
2 answers:
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C.) -4, -7/5, 1/6, 1.6,
= 2.45
1.6
1/6 = 0.167
-7/5 = -1.4
-4
C.) -4, -7/5, 1/6, 1.6,
= 2.45
1.6
1/6 = 0.167
-7/5 = -1.4
-4