The domain of the function f(x) is where the area under the square root (aka the radicand) is positive or zero. We have to write that the radicand is greater than or equal to zero, so
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C
You should be able to set up a proportion between the sides something like (18+x)/x=(56+21)/56
Answer:
-4x +3
Step-by-step explanation:
Given the functions f(x) = -2x + 3 and g(x) = 2x We are to find the composite function (f*g(x))
(f*g(x)) = f(g(x))
f(g(x)) = f(2x)
f(2x) = -2(2x) + 3
f(2x) = -4x +3
Hence f(g(x)) = -4x +3
Answer:
2.5 • 10^6
Explanation:
In order for 25 • 10^6 to be written in standard form, the ‘25’ needs to be less than 10. To do that we will move the decimal one place to the left so that 25 is now 2.5; it is now a number less than 10. It should now look like 2.5 • 10^6. It is now in standard form.
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
