Which algebraic expression represent the verbal expression "5 less than a number"?

dangina [55]

Answer:

67/5 = 13 2/5

Step-by-step explanation:

Step 1: Define/explain.

An easier way to solve this is by changing the mixed fractions to improper fractions.

To do this, multiply the whole number by the denominator, then add the product to the numerator; the denominator remains the same.

Mixed fraction - a fraction with a whole number.

Improper fraction - a fraction with a numerator larger than the denominator.

Step 2: Solve.

$8\frac{3}{5} =\frac{43}{5}$

$4\frac{4}{5} =\frac{24}{5}$

From here, add as usual.

$\frac{43}{5} +\frac{24}{5} =\frac{67}{5}$

Step 3: Conclude.

You can change the improper fraction to a mixed fraction if you'd like.

To do this, divide the numerator by the denominator.

The amount of times the numerator evenly goes into the denominator is the whole number.

The amount of remaining numbers in the denominator.

The numerator remains the same.

$\frac{67}{5} =13\frac{2}{5}$

I, therefore, believe the answer to this is 13 2/5.

5 0

3 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

6 0

3 years ago

Write each word form in standard form. Four thousand

oksano4ka [1.4K]

4,000 +000 +00 + 0 is stander form for four thousand

3 0

3 years ago

Read 2 more answers

Mr. Sen wants to treat a group of friends either to the movies or to a hockey game for his birthday. Both the theater and the ho

monitta

Answer:

there's no numbers to answer this question

Step-by-step explanation:

I apologize but all the information and table is gone there is no way to answer this for you

8 0

2 years ago

The following data shows wind speed in a city, in miles per hour, on consecutive days of a month:

shusha [124]

In the data shown, rearranging the data [9.4, 9.2, 9.7, 9.8, 9.4, 9.7, 9.6, 9.3, 9.2, 9.1, 9.4] from the least to the greatest would give us the following data set:

9.1, 9.2, 9.2, 9.3, 9.4, 9.4, 9.4, 9.6, 9.7, 9.7, 9.8

The box-plots uses a 5-number summary. The minimum value, then Q1 which is the media of the lower half of the set, Q2 which is the median of the total set, Q3 which is the median of the upper half of the set, and Q4 which is the highest number. Among the choices, the correct answer is B.

8 0

3 years ago