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zalisa [80]
2 years ago
13

Point G is located at (6, 2) on the coordinate plane. Point G is reflected over the y -axis to create point G^ prime . What orde

red pair describes the location of G?
Mathematics
1 answer:
Lilit [14]2 years ago
5 0

Answer:

The ordered pair that best describes the location of G' is (-6,2).

Step-by-step explanation:

Reflecting a point over the y-axis:

When a point (x,y) is reflected over the y-axis, it's x coordinate is multiplied by -1, while the y-coordinate stays the same. Thus:

(x,y) -> (-x,y).

Point G is located at (6, 2)

When reflected over the y-axis:

G'(-6,2).

The ordered pair that best describes the location of G' is (-6,2).

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Ronch [10]
1/2 hour. 30/60 = 1/2 3 divided by 6 is 1/2 since it's not possible for it to be 1
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3 years ago
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PLEASE HELP ME.....
Virty [35]

Answer:

They would meet each other at 01 : 24 PM.

Step-by-step explanation:

  • Erik took a trip to see his friend Mike who lives 308 miles away.
  • He left his place at 10 AM driving at 70 mph.
  • In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.

As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means

Erik left his place at 12:00 PM noon.

so, at 12:00 PM Erik had already traveled:

                                                                      2\times 70=140\:\:miles

Miles left =308-140=168\:\:miles

Let 't' be the time when they meet

so

70t\:+\:50t\:=168

120t=168

\mathrm{Divide\:both\:sides\:by\:}120

\frac{120t}{120}=\frac{168}{120}

t=\frac{7}{5}

so

t=\frac{7}{5}=1.4\:\:hours

or 1 hour and 24 minutes after 12:00 noon

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12\:+\:1.4\:=1\:O'clock\:+\:24\:minutes

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7 0
3 years ago
What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3
Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

                                         = 11 × 8

                                         = 88 square units

Area of trapezoid OGEF = \frac{1}{2}(b_1+b_2)\times h

                                         = \frac{1}{2}(\text{GE+OF)}\times (\text{OG})

                                         = \frac{1}{2}(3+6)\times 4

                                         = 18 units²

Area of trapezoid GCDE = \frac{1}{2}(\text{GC+DE)}\times (\text{GE})

                                         = \frac{1}{2}(7+2)\times 3

                                         = 13.5 units²

Area of triangle AFH = \frac{1}{2}(\text{Base})\times (\text{Height})

                                  = \frac{1}{2}(5)(2)

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Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

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                                           = 88 - 36.5

                                           = 51.5 units²

Therefore, area of the given polygon is 51.5 units²

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What we know:

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