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egoroff_w [7]
3 years ago
15

A volleyball reaches its maximum of 13 feet, 3 seconds after it is served. What quadratic formula could model the height of the

volleyball over time after it is served.
Mathematics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

H=-(t-3)^2+13

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

y=-a(x-h)^2+k

Where (h,k) is the vertex of the parabola and 'a' is a constant.

Now, let 'h' be the vertical height and 't' be the time taken.

So, the equation would be of the form:

H=-a(t-h)^2+k

Now, as per question:

h = 2 seconds, k = 13 feet.

H=-a(t-3)^2+13

Now, taking a = 1. So, the formula that can be used is:

H=-(t-3)^2+13

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T.C ( 1.1007 ) = T.C_min = $2252  

Step-by-step explanation:

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Find the least expensive price for which you can bill the job

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              T.C ( x ) = C_w*sqrt ( x^2 + 3.5^2 ) + C_g*(10 - x )

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