Question

A volleyball reaches its maximum of 13 feet, 3 seconds after it is served. What quadratic formula could model the height of the volleyball over time after it is served.

Answer 1

Answer:

$H=-(t-3)^2+13$

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

$y=-a(x-h)^2+k$

Where $(h,k)$ is the vertex of the parabola and 'a' is a constant.

Now, let 'h' be the vertical height and 't' be the time taken.

So, the equation would be of the form:

$H=-a(t-h)^2+k$

Now, as per question:

h = 2 seconds, k = 13 feet.

$H=-a(t-3)^2+13$

Now, taking a = 1. So, the formula that can be used is:

$H=-(t-3)^2+13$