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kykrilka [37]
3 years ago
7

I'm tragically single just to put that out there

Mathematics
1 answer:
EastWind [94]3 years ago
3 0

Same I hate tiktoc for showing me happy couples

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Evaluate : X + 2 ( x -20) (4)<br> for x = 10
Oxana [17]

Answer:

x + 2 ( x - 20 )( 4 ) = -70

Step-by-step explanation:

hope this helps. . .<3

6 0
3 years ago
The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

y(x)=c1cosβx+c2sinβx

therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

y''+10y=0

this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

5 0
3 years ago
What is the value of 3 in number 234
Nonamiya [84]
30 because it is in the tenths place
7 0
3 years ago
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3x +6= 27<br> x =<br> how do you solve this.
Serjik [45]
3x + 6 = 27

step 1. subtract 6 from both sides

3x = 21

step 2. divide both sides by three to get x alone

x = 7

hope this helps
8 0
4 years ago
Read 2 more answers
Choose all of the statements that correctly compare the two functions shown.
Kisachek [45]
The 1st one is true
the 2nd one is false
the 3rd one is false
the 4th one is true
the 5th one is true
8 0
3 years ago
Read 2 more answers
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