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3 years ago

9

jay runs 1 1/2 miles at track practice. Teddy run the 100 yard dash, and Cadi runs half as far as Jay. how many yards do they ru

n?

1 answer:

arsen [322]3 years ago

8 0

Jay ran 2650 yards and Cadi ran 1320 yards.

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Someone pleaseee help meeee

horrorfan [7]

Ill tell you the answer if u mark me brainliest

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3 years ago

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Please need help thank

Svetlanka [38]

183.75 because if you did $1470 then divided it by 8 it would =183.75

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3 years ago

If i drive at a constant rate and go 100 miles in 2 hours, write an equation that could represent the number of miles, m, per ho

Ipatiy [6.2K]

100 miles ............... 2 hours
x miles ................1 hour

x = 100 m / 2 h = 50 m / h

5 0

4 years ago

Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.

solniwko [45]

For this case we have to:

Let $u = x + 1$

So:

$u ^ 2-4u + 2 = 0$

We have the solution will be given by:

$u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Where:

$a = 1\\b = -4\\c = 2$

Substituting:

$u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}$

The solutions are:

$u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}$

Returning the change:

$2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}$

Answer:

$x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}$

3 0

3 years ago

Read 2 more answers

Identify the sequence graphed below and the average rate of change from n = 1 to n = 3. coordinate plane showing the point 2, 10

Katena32 [7]

Answer:

geometric sequence with initial value 20 and common ratio 1/2
average rate of change on [1, 3] = -7.5

Step-by-step explanation:

(a) The given points have sequential values of x and values of y that are each 1/2 the value before. The common ratio tells us the sequence is a geometric sequence.

(b) The first given point is (2, 10), so extrapolating backward, we determine the previous point to be ...

... (2-1, 10/(1/2)) = (1, 20)

Thus, we have enough information to determine the average slope between n=1 and n=3.

... (difference in y)/(difference in n) = (5 -20)/(3 -1) = -15/2 = -7.5

4 0

3 years ago