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LenKa [72]
4 years ago
13

Write a polynomial equation that is best represented by the graph. Please show work and thanks in advance! :)

Mathematics
2 answers:
crimeas [40]4 years ago
4 0
(x+1)(x)(x-2)
I checked my graphing calculator to make sure!
kipiarov [429]4 years ago
3 0
It's a 3rd degree polynomial judging by the shape.  Use the 3 factored zeros of x=-1,0,2 to get x(x+1)(x-2)
multiply this out to get
y=x^3-x^2-2x
I plotted it too

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If c – 8 is an odd integer, which of the following could be the value of c?
finlep [7]

Answer:

Since you didn't give me any choices I can tell you that c is ANY ODD NUMBER THAT EXISTS.

Step-by-step explanation:

im smart ツ

7 0
3 years ago
5% of what number is 85?
Semmy [17]
5% = 0.5

0.5n = 85

Divide by 0.5

0.5n = 85
/0.5      /0.5

n = 170.

The number is 170.
8 0
4 years ago
Sandra saves 7% of her salary for retirement. This year her salary was $2,000 more than her salary than in the previous year, an
Effectus [21]

9514 1404 393

Answer:

  • 2,000
  • $45,000

Step-by-step explanation:

Where x represents the previous year's salary, its amount this year is said to be ...

  x + 2000

The equation is trying to reflect the fact that 7% of that is $3,290. The missing number is 2000:

  0.07(x +2000) = 3290

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Solving for x, we find ...

  x = (3290/0.07) -2000 = 45000

Sandra's salary the previous year was $45,000.

3 0
3 years ago
Use the picture <br> QRS = ____<br> By ___
Xelga [282]

Answer:

TWX by AAS

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3 0
3 years ago
A company has 200 machines. Each machine has 129 probability of not working. If you were to pick 40 machines randomly, the proba
alexgriva [62]

The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.

Given a company has 200 machines. Each machine has a 12% probability of not working.

If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.

So

1) probability that 5 would not be working

C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵

                                ≈ 0.18665

2)  probability that at least one machine would be working

0.88⁴⁰ ≈ 0.00602

3) probability that all would be working

1 - 0.12⁴⁰ ≈ 1.0000

Learn more about probability here: brainly.com/question/24756209

#SPJ10

7 0
2 years ago
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