We are given
First equation:
we can use formula
slope is m=1
y-intercept is b=-1
Second equation:
we can use formula
slope is m=-2
y-intercept is b=5
Graph:
We can see that
both curves intersect at (2,1)
so, solution is x=2 and y=1.................Answer
1. Let's call:
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
Answer:
4 ( m⁶ - 4p¹⁰ )
Step-by-step explanation:
4m⁶ = 4 * m⁶
16p¹⁰= 4 * 4 * p¹⁰
Common factor = 4
4m⁶ - 16p¹⁰ = 4 ( m⁶ - 4p¹⁰ )
