Which equation is a related equation

You pay $2.36 for 6 donuts. What is the unit price

kolezko [41]

Answer:

39 cents per donut

Step-by-step explanation:

2.36 / 6 = 0.39333333333

Round cents to the nearest hundredth

Hope this helps

-IronWolfX

7 0

3 years ago

Read 2 more answers

A snowcone cup at the country fair is 15 cm tall and has a diameter of 8 cm if the cup is full just the top what is the volume o

slavikrds [6]

Answer:

2827 cubic centimetre

Step-by-step explanation:

The cup is cylindrical in shape and it is full to the top.

The height of the cup is 15 cm and its diameter is 8 cm (radius = 4 cm).

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius

h = height

The volume of the liquid in the cup is:

$V = \pi * 15^2 * 4$

V = 2827.43 cubic centimetre ≅ 2827 cubic centimetre

3 0

3 years ago

Solve the above que no. 55

aleksandr82 [10.1K]

Answer:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

2) $\left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)$ $\tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}$

3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

Step-by-step explanation:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

2) $\left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)$ $\tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}$

3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

4 0

3 years ago

P=b+4a+c, solve for b

scoray [572]

First subtract the C to move it to the other side

c-P=b+4a

Then subtract the 4a as well

4a-c-p=b

4 0

4 years ago

Read 2 more answers

Anton defines an acute angle as an angle that is not obtuse. Is Anton's definition valid ?

kobusy [5.1K]

Answer:

Anton's definition is not valid.

Step-by-step explanation:

We have been given that Anton defines an acute angle as an angle that is not obtuse. We are asked to find whether Anton's definition is valid or not.

We know that an angle is known as acute angle whose measure is greater than 0 and less than 90 degrees.

We also know that an angle is known as obtuse angle whose measure is greater than 90 degrees and less than 180 degrees.

We know that a right triangle is neither acute nor obtuse. Since Anton hasn't mentioned a right triangle to his definition, therefore, his definition is not valid.

4 0

3 years ago