Question

Urgent need the answers plz help.

Answer 1

Answer:

(a) $P" = (-4,-3)$

(b) $(x,y) \to (4,-8)$

Step-by-step explanation:

Given

$P = (4,3)$

Solving (a): Reflect across x and y-axis.

Reflection across x-axis has the following rules

$(x,y) \to (x,-y)$

So, we have:

$P' = (4,-3)$

Reflection across y-axis has the following rules

$(x,y) \to (-x,y)$

So, we have:

$P" = (-4,-3)$

Hence, the new point is: (-4,-3)

Solving (b): Rx . Do,2 (2,4)

$R_x \to$ reflect across the x-axis

Reflection across x-axis has the following rules

$(x,y) \to (x,-y)$

So, we have:

$(2,4) = (2,-4)$ ---- when P is reflected across the x-axis

$D_{o,2} \to$ dilate by a scale factor of 2

The rule is:

$(x,y) \to 2 * (x,y)$

So, we have

$(x,y) \to 2 * (2,-4)$

Open bracket

$(x,y) \to (4,-8)$