The angle relationship and their reasons are:
- m∠HED = m∠FEJ ---> Vertical angles theorem
- m∠KFE = m∠DEH ---> Alternate interior angles theorem
- m∠LFG = m∠DEH ---> Alternate exterior angles theorem
- m∠JEF + m∠LFE = 180° ---> same-side interior angles theorem
- m∠DEJ = m∠EFL ---> Corresponding interior angles theorem
- m∠LFG + m∠GFK = 180 ---> linear pair
The angle pairs are formed based on their relative positions. The following shows each angle relationship and their reasons:
∠HED and ∠FEJ are directly vertically opposite each other, therefore, they are equal based on the vertical angles theorem.
- m∠HED = m∠FEJ ---> Vertical angles theorem
∠KFE and ∠FEJ are alternate interior angles, therefore, they are equal based on the alternate interior angles theorem.
- m∠KFE = m∠DEH ---> Alternate interior angles theorem
∠LFG and ∠FEJ are alternate exterior angles, therefore, they are equal based on the alternate exterior angles theorem.
- m∠LFG = m∠DEH ---> Alternate exterior angles theorem
∠JEF and ∠LFE are interior angles on same side of the transversal, therefore, the sum of both angles equal 180 degrees based on the same-side interior angles theorem.
- m∠JEF + m∠LFE = 180° ---> same-side interior angles theorem
∠DEJ and ∠EFL are corresponding angles, therefore, they are equal based on the corresponding angles theorem.
- m∠DEJ = m∠EFL ---> Corresponding interior angles theorem
∠LFG and ∠GFK are angles on a straight line, therefore the sum of both angles will equal 180 degrees because they are a linear pair.
- m∠LFG + m∠GFK = 180 ---> linear pair
Learn more about angle relationship on:
brainly.com/question/12591450
Answer:
1/2 is poured out and 1 1/2 is left
Step-by-step explanation:
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
