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CaHeK987 [17]
3 years ago
5

Maury has 8 plants three are flowers and 5 are ferns what fraction oh his plants are frens

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0
(5/8) 5 out of the 8 are ferns, which would make the fraction 5/8
rjkz [21]3 years ago
3 0
5/8 are ferns. if there are 8 plants and three flowers the flowers don't matter because all you are looking for are ferns
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Find the volumes of the solids generated by revolving the triangle with vertices (2, 2)​, (2, 6)​, and (5, 6) about ​a) the​ x-a
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  • About the x-axis (washer method):

\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}

  • About the y-axis (shell method):

\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}

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  • About y=2 (washer method):

\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}

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A single​ 6-sided die is rolled twice. The set of 36 equally likely outcomes is​ {(1,1), (1,2),​ (1,3), (1,4), left parenthesis
Dennis_Churaev [7]

Answer:

The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

Step-by-step explanation:

Given : A single​ 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

          1              2              3              4               5             6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}

\text{Probability}=\frac{6}{36}

\text{Probability}=\frac{1}{6}

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

5 0
4 years ago
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