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Lunna [17]
3 years ago
6

The groundhog population of​ Punxsutawny, Pennsylvania is closely monitored each year. Two years ago the population decreased by

​ 12%. Last year the number of groundhogs increased by​ 6%. This year the population also increased by​ 9%. What was the percentage​ increase/decrease of groundhogs over these three​ years? Round your answer to the nearest tenth of a percentage poin
Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer:

There was a increase of 1.7% over these three​ years

Step-by-step explanation:

Multipliers:

For a decrease of a%, we multiply by: \frac{100-a}{100}

For a increase of a%, we multiply by: \frac{100+a}{100}

What was the percentage​ increase/decrease of groundhogs over these three​ years?

Decrease of 12%(multiplication by 0.88).

Increase of 6%(multiplication by 1.06).

Increase of 9%(multiplication by 1.09).

After these three years:

0.88*1.06*1.09 = 1.017

1.017 - 1 = 0.017

0.017*100% = 1.7%

There was a increase of 1.7% over these three​ years

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The empirical probability, also called experimental probability of an event is the ratio of the number of outcomes in which a specified event occurs to the total number of trials, not in a theoretical sample space but in an actual experiment.

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It's an actual result of an experiment, hence the 12/14 = 0.86 = 86% that he spills his lunch on himself tomorrow.

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