Answer:
75000
hope this helps u
brainliest pls
Step-by-step explanation:
Let 7.1239 is a decimal number. Now, we have to round the given decimal number to its nearest thousandth.
Step 1: Identity the thousandth digit. (Here, 3 is the digit which is in thousandth place)
Step 2: Now, look at the digit, which is next to the thousandth place. If that digit is less than 5, round down the thousandth digit. If that digit is greater than or equal to 5, round up the thousandth digit. From the example given above, the digit next to the thousandth digit (i.e., 9) is greater than 5, so we have to round up the thousandth digit.
Step 3: Thus, the number 7.1239 rounded to the nearest thousandth is 7.124.
2m would be your answer
Each ticket costs $2, which means that if you are buying more tickets, it would look like: 2 + 2.... instead of the others
hope this helps
Answer:
10
Step-by-step explanation:
The question is wrong it should be 5C3
5C3=5!/((5-3)!•3!)=5!/(2!•3!)
=(5•4•3•2•1)/(2•1•3•2•1)
=10
Answer:
The value of ROE that will be exceeded by 78% of the firms is -1.77%.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The mean ROE for the firms studied was 14.93% and the standard deviation was 21.74%. This means that 
What value of ROE will be exceeded by 78% of the firms?
This is the value of X when Z has a pvalue of 1-0.78 = 0.22.
This is 
So:




The value of ROE that will be exceeded by 78% of the firms is -1.77%.
1. 5+4
2. 7+2
The answer is 9.
I hope I helped! :)