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Lorico [155]
3 years ago
6

Find the slope of every line that is perpendicular to this one

Mathematics
1 answer:
elixir [45]3 years ago
7 0

-1/3 slope will make another perpendicular line

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Mrs. Eaton's class is participating in the "Box Tops for Education" campaign. On the first day, her
storchak [24]
Each colection day: D
Number of tops collected on that day: N

D1=1; N1=2
D2=3; N2=8

1) Linear model
N-N1=m(D-D1)

m=(N2-N1)/(D2-D1)
m=(8-2)/(3-1)
m=(6)/(2)
m=3

N-N1=m(D-D1)
N-2=3(D-1)
N-2=3D-3
N-2+2=3D-3+2
N=3D-1

when D=6:
N=3(6)-1
N=18-1
N=17

<span>What is the number of tops collected on the sixth day based on the linear model?
</span>The number of tops collected on the sixth day based on the linear model is 17.

2) Exponential model
N=a(b)^D
D=D1=1→N=N1=2→2=a(b)^1→2=ab→ab=2   (1)

D=D2=3→N=N2=8→8=a(b)^3→8=a(b)^(1+2)
8=a(b)^1(b)^2→8=ab(b)^2   (2)

Replacing (1) in (2)
(2) 8=2(b)^2
Solving for b:
8/2=2(b)^2/2
4=(b)^2
sqrt(4)=sqrt( b)^2 )
2=b
b=2

Replacing b=2 in (1)
(1) ab=2
a(2)=2
Solving for a:
a(2)/2=2/2
a=1

Then, the exponential model is N=1(2)^D
N=(2)^D

When D=6:
N=(2)^6
N=64

<span>What is the number of tops collected on the sixth day based on the exponential model?
</span><span>The number of tops collected on the sixth day based on the exponential model is 64</span>
7 0
4 years ago
the speed limit on a highway is 110 km per hour. how much time does it take a car to travel 132 km at this speed
satela [25.4K]

Given:

Speed limit on a highway is 110 km per hour.

Let x be the speed of the car in time 't'

t\ge\frac{x}{110}

time when taken for a car to travel 132km.

\begin{gathered} t\ge\frac{132}{110} \\ t\ge1.2\text{ hours} \end{gathered}

It takes minimum 1 hour 12 minutes

6 0
1 year ago
X - 14 = 6 - 3(x - 4)<br> step by step
Leona [35]

Answer:

16

Step-by-step explanation:

look at picture

6 0
3 years ago
Using the diagram below, which of the following proportionality statements are true? Select all that apply.
Shkiper50 [21]

Answer:

The proportionality statement which is true is;

(B) \dfrac{G'H'}{GH} = \dfrac{E'F'}{EF}

Step-by-step explanation:

From the diagram, given that the two pentagons are similar, we have;

1. \dfrac{DH}{D'H'}  = \dfrac{EF}{E'F'}

2. \dfrac{DE}{D'E'}  = \dfrac{GH}{G'H'}

By similarity of the two polygons, we can get the following statements from among the options;

3. \dfrac{G'H'}{GH} = \dfrac{E'F'}{EF}

Therefore, the proportionality statement which is true from the given is the statement;

\dfrac{G'H'}{GH} = \dfrac{E'F'}{EF}

3 0
3 years ago
A street vendor sells popcorn in different size bags (small, medium, large, extra large, jumbo, and gigantic). For each size, th
wel

Answer:

56

Step-by-step explanation:

Bag sizes: 7

Flavors: 4

multiply 7×4= 28

and 28×2, because there are two kinds of popcorn, salted and unsalted

28×2= 56

I think this is the answer :l

5 0
3 years ago
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