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Lana71 [14]
3 years ago
14

A street vendor sells popcorn in different size bags (small, medium, large, extra large, jumbo, and gigantic). For each size, th

ere are different flavors (chili-lime, cheese, butter, and jalapeno), and for each flavor you may choose salted or unsalted popcorn. How many different bags of popcorn can the vendor make?
Mathematics
1 answer:
wel3 years ago
5 0

Answer:

56

Step-by-step explanation:

Bag sizes: 7

Flavors: 4

multiply 7×4= 28

and 28×2, because there are two kinds of popcorn, salted and unsalted

28×2= 56

I think this is the answer :l

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Evaluate the expression 2v^3•v^0
alekssr [168]

Answer:

2v^3

Step-by-step explanation:

hope it helps ;)

6 0
3 years ago
Find the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) dx x(l
Pepsi [2]

I'm assuming the integral is

\displaystyle \int \frac{dx}{x (\ln(x^2))^5}

We have

\ln(x^2) = 2 \ln|x| \implies (\ln(x^2))^5 = 32 (\ln|x|)^5

Then substituting y=\ln|x| and dy=\frac{dx}x, the integral transforms and reduces to

\displaystyle \int \frac{dx}{x(\ln(x^2))^5} = \frac1{32} \int \frac{dy}{y^5} \\\\ ~~~~~~~~ = \frac1{32} \left(-\frac1{4y^4}\right) + C \\\\ ~~~~~~~~ = -\frac1{128(\ln|x|)^4} + C

which we can rewrite as

128 (\ln|x|)^4 = 8\cdot2^4(\ln|x|)^4 = 8 (2\ln|x|)^4 = 8 (\ln(x^2))^4

and so

\displaystyle \int \frac{dx}{x (\ln(x^2))^5} = \boxed{-\frac1{8(\ln(x^2))^4} + C}

7 0
2 years ago
The area of David's living room is 18.087 square yards, and their bedroom has an area of 15.78 square yards.Round to the nearest
Darina [25.2K]
Q. The area of David's living room is 18.087 square yards, and their bedroom has an area of 15.78 square yards.Round to the nearest tenth and estimate the amount of carpet they need to buy. PLZ HELP!!

A. 33.867 and rounded is 33.9
7 0
3 years ago
100 POINTS EZ |
ehidna [41]
  • Area of the quadrilateral=1/2×diagonal×(sum of perpendiculars)

Put the values

Area:-

\\ \rm\Rrightarrow \dfrac{1}{2}(24)(8+13)

\\ \rm\Rrightarrow 12(21)

\\ \rm\Rrightarrow 252m^2

7 0
2 years ago
Read 2 more answers
The area of a rectangle is 56 cm. The length is 2cm more than x and width is 5 cm less than twice x. Solve for x. Round to the n
ra1l [238]
Area = Length * Width = l * w
l = x + 2
w = 2x - 5
Area = (x + 2)(2x - 5) = 56
Area = 2x^2 -x  - 10 = 56
Area = 2x^2 - x - 66 = 0 Now you have to factor this thing.
Area = (2x + 11)( x - 6) = 0 This is more or less done by guessing. 
2x + 11 = 0 can't work. x would be negative.
x - 6 = 0
x = 6.

Check
=====
l = x + 2
l = 6 + 2
l = 8

w = 2*x - 5
w = 2*6 - 5
w = 12 - 5
w = 7

l*w = 8*7 = 56. It checks.
If this is the best answer you get, could you consider a Brainly? I need 2 of them to move up.
3 0
4 years ago
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