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4 years ago

6

Solve 4=1+x for the property of equality

2 answers:

ICE Princess25 [194]4 years ago

7 0

The answer is x=3 is your answer

posledela4 years ago

4 0

You put x left and 4 right while changing sign. You get x=4-1=3

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Points D, E, and F are on circle C and EF ≅ DF. What is the measure of ∠CDF?

antiseptic1488 [7]

The answer is

26 degrees

I just did the test hope this helps :)

6 0

3 years ago

Read 2 more answers

Alicia receives 2/5 of a $120 gift, and Jason receives 1/3 of the gift. What is the ratio of Jason's share to Alicia's share? Ex

maria [59]

Answer:

5/6

Step-by-step explanation:

Step 1: Find Alicia's share of the gift. To do this, all you have to do is multiply 120 by 2/5, which is 40%. 120 * 40% (0.4) is 48. Alicia's share is $48.

Step 2: Find Jason's share of the gift. In this case, divide 120 by 3. 120/3 is 40. Jason's share is $40.

Step 3: Express the numbers as a fraction and simplify it. 40/48 is the common fraction. Find the GCF of 40 and 48. When you solve for it, the GCF is 8. Divide both the numerator and the denominator by 8. 40/8 is 5/ 48/8 is 6. There. 5/6 is our simplified fraction, which is the ratio.

8 0

3 years ago

Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round

Karo-lina-s [1.5K]

Answer:

1. D. $50\text{ units}^2$

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of base line of our triangle we will get,

$\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}$

$\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}$

$\text{Base length of triangle}=\sqrt{100+100}$

$\text{Base length of triangle}=\sqrt{200}$

$\text{Base length of triangle}=10\sqrt{2}$

Now let us find the height of triangle similarly.

$\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}$

$\text{Height of triangle}=\sqrt{(5)^2+(5)^2}$

$\text{Height of triangle}=\sqrt{25+25}$

$\text{Height of triangle}=\sqrt{50}$

$\text{Height of triangle}=5\sqrt{2}$

$\text{Area of triangle}=\frac{\text{Base*Height}}{2}$

$\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}$

$\text{Area of triangle}=\frac{50*2}{2}$

$\text{Area of triangle}=50$

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

$\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}$

$\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}$

$\text{Large side of rectangle}=\sqrt{169+169}$

$\text{Large side of rectangle}=\sqrt{338}$

$\text{Large side of rectangle}=13\sqrt{2}$

$\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}$

$\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}$

$\text{Small side of rectangle}=\sqrt{9+9}$

$\text{Small side of rectangle}=\sqrt{18}$

$\text{Small side of rectangle}=3\sqrt{2}$

$\text{Perimeter of rectangle}=2(\text{Length + Width)}$

$\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}$

$\text{Perimeter of rectangle}=2(16\sqrt{2}}$

$\text{Perimeter of rectangle}=32\sqrt{2}$

$\text{Perimeter of rectangle}=45.2548339959390416\approx 45$

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

8 0

4 years ago

Read 2 more answers

Solve for x. a=1/2h(b x)

fredd [130]

A = 1/2 h(b + x)
2a = h(b + x)
2a/h = b + x
x = 2a/h - b

5 0

4 years ago

Can you please help me with these questions ):

Makovka662 [10]

It is-12 for the determination

6 0

3 years ago