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Rudik [331]
3 years ago
8

Fertilizer is sold in 100 pound bags labelled with the amount of nitrogen ( N), phosphoric acid ( P2O5), and potash ( K2O) prese

nt. The mixture of these nutrients varies from one type of fertilizer to the next. For example, a 100100 pound bag of Vigoro Ultra Turf fertilizer contains 2929 pounds of nitrogen, 33 pounds of phosphoric acid, and 44 pounds of potash. Another type of fertilizer, Parkerâs Premium Starter, has 1818 pounds of nitrogen, 2525 pounds of phosphoric acid, and 66 pounds of potash per 100100 pounds. Determine the amount of each type required to yield a mixture containing the 170170 pounds of nitrogen, 8787 pounds of phosphoric acid, and 3434 pounds of potash
Mathematics
1 answer:
Grace [21]3 years ago
6 0

Answer:

For Vigoro are needed

2929*35.8479 ≅ 104,988.49 (N)

33*3.4351≅113.35 (A)

44*31.2181≅1373.59 (P)

For Parkera are needed

1818*35.8479≅65,171.48 (N)

2525*3.4351≅8673.62 (A)

66*31.2181≅2060.39 (P)

Step-by-step explanation:

we have that in every 100100 pounds of compound nitrogen (N), phosphoric acid (A) and potash (P) are present and that according to the product brand the concentrations vary, therefore:

For Vigoro

2929 N, 33 A, 44 P

For Parkeras

1818 N, 2525 A, 66 P

Now, we need 170170 N, 8787 A and 3434 P of final product containing the components of the types of fertilizers

You can see that the compounds are the same what changes are the proportions from there that

2929N+1818N=170170 ⇒ 4747N=170170 ⇒ N=170170/4747 ≅ 35.8479

33A+2525A=8787 ⇒ 2558A=8787 ⇒ A=8787/2558  ≅ 3.4351

44P+66P = 3434 ⇒ 110P=3434 ⇒ P=3434/110 ≅ 31.2181

Finally

For Vigoro are needed

2929*35.8479 ≅ 104,988.49 (N)

33*3.4351≅113.35 (A)

44*31.2181≅1373.59 (P)

For Parkera are needed

1818*35.8479≅65,171.48 (N)

2525*3.4351≅8673.62 (A)

66*31.2181≅2060.39 (P)

Note: to verify the data, just replace the values ​​in the equations

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Answer:

(26, \frac{57}{2})

Step-by-step explanation:

Hi there!

We are given the coordinates (26, 56) and (26, 1)

We want to find the midpoint of these two points

The midpoint can be found using the formula (\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2}), where (x_1, y_1) & (x_2, y_2) are points

We have 2 points, which is what we need to find the midpoint, but let's label the values of the points to avoid confusion and mistakes when actually calculating

x_1=26\\y_1=56\\x_2=26\\y_2=1

Now substitute these values into the formula.

(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2})

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Add the numbers together

(\frac{52}{2} , \frac{57}{2})

Divide

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Hope this helps!

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Answer: b) rolled three times, number of 2s rolled

              d) rolled twice, number of odds rolled

<u>Step-by-step explanation:</u>

A binomial experiment must meet the following criteria:

  1. There must be a fixed number of trials (rolls)
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a) rolled twice --> satisfies #1 & #2 (n = 2)

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b) rolled three times --> satisfies #1 & #2 (n = 3)

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Step-by-step explanation:

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Given parameters:

   Coordinates of the points =  (3,4) and (19, 16)

Unknown:

The distance between the points = ?

The midpoint  = ?

Solution:

  The distance between two points can be mathematically solved using;

    D  = \sqrt{(x_{2} - x_{1})^{2}  + (y_{2} - y_{1})^{2}  }

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Midpoint;

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