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3 years ago

Pls help:) (geometry)

Mathematics

1 answer:

dybincka [34]3 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

(15)

Since BE bisects ∠ ABD then ∠ DBE = ∠ ABE, thus

8x - 14 = 6x + 2 ( subtract 6x from both sides )

2x - 14 = 2 ( add 14 to both sides )

2x = 16 ( divide both sides by 2 )

x = 8

Thus ∠ ABE = 6x + 2 = 6(8) + 2 = 48 + 2 = 50°

(16)

Since BE bisects ∠ ABD then ∠ ABE = ∠ DBE = 12n - 8 and

∠ ABD = ∠ ABE + ∠ DBE, that is

22n - 11 = 12n - 8 + 12n - 8 = 24n - 16 ( subtract 24n from both sides )

- 2n - 11 = - 16 ( add 11 to both sides )

- 2n = - 5 ( divide both sides by - 2 )

n = 2.5

Thus

∠ EBD = 12n - 8 = 12(2.5) - 8 = 30 - 8 = 22°

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Answer:

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3 years ago

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3 years ago

Read 2 more answers

I'm stuck and really need help. I can't figure out the rest.

Ad libitum [116K]

Answer:

The next statements are are;

Statement ${}$ Reason

Segment $\overline {DC}$ ≅ Segment $\overline {AB}$ ${}$ CPCTC

$\overline {AD}$ ≅ $\overline {BC}$ and $\overline {DC}$ ≅ $\overline {AB}$ , therefore;

ABCD is a parallelogram ${}$ Parallelogram side theorem

Step-by-step explanation:

Statement ${}$ Reason

Segment $\overline {DC}$ ≅ Segment $\overline {AB}$ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

Given that $\overline {AD}$ ≅ $\overline {BC}$ and we have that $\overline {DC}$ ≅ $\overline {AB}$ , we get;

ABCD is a parallelogram ${}$ Parallelogram side theorem

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3 years ago

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4 years ago