Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
250 - 5(x) = 50
250 (-250) - 5x = 50 (-250)
-5x = -200
-5x/-5 = -200/-5
x = 40
hope this helps
you are 40 years old!
1 is the answer.
The exact answer is 1.03, but we have to round it to the nearest tenth which is 0 because 3 is less than 5.
Answer:
The general rate of change can be found by using the difference quotient formula. To find the average rate of change over an interval, enter a function with an interval:
f
(
x
)
= x
^2
, [
2
,
3
]
The rate of Change is 2
Step-by-step explanation:
