All categories

2 years ago

Which of the following inequalities represents the number line below?

Mathematics

1 answer:

gregori [183]2 years ago

5 0

Answer:

x ≤ 4

Step-by-step explanation:

the solid dot at 4 indicates that x can equal 4

the arrow points to the left indicating values less than 4 , then

x ≤ 4

You might be interested in

I am making quilts out of my grandma's square handkerchief collection. I have

Yuki888 [10]

Answer:

32 quilts with 11 left over

Step-by-step explanation:

4 0

2 years ago

You have a coupon for $5 off an oil change. When you arrive at the auto repair

Anestetic [448]

The function that represents how much you would pay is:

p(x) = (x - $5)*0.9

<h3>How to find the function?</h3>

Let's say that the cost of the repair is x.

First, we apply the coupon, so we discount $5 for the cost.

x - $5.

Then we apply another discount of the 10%, this is written as:

(x - $5)*(1 - 10%/100%)

(x - $5)*(1 - 0.1)

(x - $5)*0.9

Then the function that represents how much you would pay is:

p(x) = (x - $5)*0.9

If you want to learn more about functions:

brainly.com/question/4025726

#SPJ1

6 0

1 year ago

ASAP Free points, please solve -2m+36=2(6m-3)?<br>

Komok [63]

Answer:

$m = 3$

Step-by-step explanation:

We can try and isolate m on one side of the equation by following the rules of simplifying equations.

$-2m + 36 = 2(6m - 3)\\\\-2m+36 = 12m - 6\\\\36 = 14m-6\\\\42 = 14m\\\\3 = m$

Hope this helped!

6 0

3 years ago

Read 2 more answers

F=(2xy +z³)i + x³j + 3xz²k find a scalar potential and work done in moving an object in the field from (1,-2,1) to (3,1,4)

Alex73 [517]

Step-by-step explanation:

Given:

$\textbf{F} = (2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}$

This field will have a scalar potential $\varphi$ if it satisfies the condition $\nabla \times \textbf{F}=0$ . While the first x- and y- components of $\nabla \times \textbf{F}$ are satisfied, the z-component doesn't.

$(\nabla \times \textbf{F})_z = \left(\dfrac{\partial F_y}{\partial x} - \dfrac{\partial F_x}{\partial y} \right)$

$\:\:\:\:\:\:\:\:\: = 3x^2 - 2x \ne 0$

Therefore the field is nonconservative so it has no scalar potential. We can still calculate the work done by defining the position vector $\vec{\textbf{r}}$ as

$\vec{\textbf{r}} = x \hat{\textbf{i}} + y \hat{\textbf{j}} + z \hat{\textbf{k}}$

and its differential is

$\textbf{d} \vec{\textbf{r}} = dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}}$

The work done then is given by

$\displaystyle \oint_c \vec{\textbf{F}} • \textbf{d} \vec{\textbf{r}} = \int ((2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}) • (dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}})$

$\displaystyle = (x^2y + xz^3) + x^3y + xz^3|_{(1, -2, 1)}^{(3, 1, 4)}$

$= 422$

5 0

3 years ago

Find the exact value of x. Round to the nearest tenth.

Lena [83]

X = 25

a^2 + b^2 = c^2
19^2 +16^ = c^2
617 = c^2
(Square root 617)
x=24.83
x=25

7 0

2 years ago