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Rina8888 [55]
3 years ago
9

1/2x + 3y=4 for x when x = 6

Mathematics
2 answers:
Kipish [7]3 years ago
6 0
Wouldn't it be y=1/3?
WARRIOR [948]3 years ago
4 0
½6+3y=4
3+3y=4
3y=4-3
3y=1
y=⅓
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Which statement describes the end behavior of the exponential function f(x)=2^x-3
notsponge [240]

I believe it's A. Hope it helps :)

6 0
3 years ago
The product of two consecutive integers is 420 which quadratic equation can be used to find x the lesser number
Fynjy0 [20]

Answer:

Step-by-step explanation:

If the smallest number is 'x', then the other number = x +1

x*(x+1)= 420

Use distributive property

x*x + x*1 = 420

x² + x - 420 =0   ------> this is the required quadratic equation.

5 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
3 years ago
What is the Square root of -100
lidiya [134]

Answer:

10i

Step-by-step explanation:

√(-100)

Use the imaginary number rule  i=\sqrt{-1}

√(-1) × √(100)

i × √(10²)

i × 10

= 10i

6 0
3 years ago
Read 2 more answers
Can you please help meeeeeeee
Ahat [919]
The outlier would be 68
4 0
3 years ago
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