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kaheart [24]
3 years ago
9

What is the equation of the line of best fit for these data? Round the slop

Mathematics
1 answer:
Zarrin [17]3 years ago
8 0

Answer:

the equatopion of the line of the best fit for this data will be 15

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What is the greatest common divisor of 33489, 3948, and 3949
storchak [24]

33489 = 32×612

3948 = 22×3×7×47

3949 = 11×359

GCD = 1

33489 / 1 = 33489

3948 / 1 = 3948

3949 / 1 = 3949

3 0
3 years ago
Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w
siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$  is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4} $

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0
3 years ago
Can someone help, me
Radda [10]
The answer to #5 is 33.
8 0
3 years ago
Read 2 more answers
Sam earned $380 working for 8 hours.<br> How much does Sam earn per hour? $<br> per hour
Crank

Answer:

$47.50

Step-by-step explanation:

You just take $380 and divide it by 8 hours to get the amount of money per hour, which is $47.50 .

7 0
3 years ago
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A square has a side length of 2x+5, write an expression to find the perimeter of the square
Naddika [18.5K]

Answer:

4(2x+5) or 8x+20

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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