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2 years ago

X2 + y2 - 14x + 10y + 65 = 0 will lie ENTIRELY in Quadrant

1 answer:

5 0

Rearranging to standard form
= (x - 7)^2 + (y + 5)^2 = -65 + 49 + 25
(x-7)^2 + (y+5)^2 = 9
so the centre is at (7,-5) and the radius is 3

so the circle will be entirely in Quadrant 4.

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Can someone help me round these two numbers? I completely forgot how ‍

tigry1 [53]

Answer:

Step-by-step explanation:

If you are rounding to nearest tenth

2.6 1.9

Nearest hundredth

2.6 1.87

If the number to the right of the one you want to round is 5 or above, you go up a number. If it's below, you go down 1.

Hope this helps.

5 0

2 years ago

A snowstorm began on Monday evening. It snowed steadily until 6:00 am on Tuesday morning when the snow was 12 inches deep. Kevin

poizon [28]

Answer:

what is expected at 7am is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

Step-by-step explanation:

In this question, we are asked to calculate if the prediction made by an equation modeled is correct.

Firstly let’s look at the equation in question;

y = 3t - 6

where y is the snow depth and t is the number of hours after midnight.

now we are looking at 7am, that’s 7 hours past 12am, meaning 7 hours after midnight.

let’s plug the value of t as 7 into the equation

y = 3(7) - 6

y = 21-6

y = 15 inches

according to the equation by Kevin, what is expected is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

3 0

3 years ago

Help me plz nd ty:) <br> is -13 an integer

DENIUS [597]

Answer:

yes it is an integer

Step-by-step explanation:

please mark as brainliest

3 0

2 years ago

Read 2 more answers

What are the points of discontinuity for y=x^2+3/x^2+2

mr Goodwill [35]

I don;t think there area any points of discontinuity on this graph.

5 0

3 years ago

If possible help me in this. I need to find the two odd numbers...

Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer: x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\$

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15 or -15, -13</h3>

4 0

2 years ago