Question

What is the equation in point-slope form of the line that passes through the points (7, 5)(7, 5) and (−4, −1)(−4, −1) ? y+4=116(x+1)y+4=116(x+1) y−1=611(x−4)y−1=611(x−4) y+1=611(x+4)y+1=611(x+4) y+1=67(x+4)

Answer 1

Hope this helped :)

Answer:

Answer 2

(7,5)(-4,-1)
slope = (-1-5) / (-4-7) = -6/-11 = 6/11

y - y1 = m(x - x1)
slope(m) = 6/11
(-4,-1)...x1 = -4 and y1 = -1
now we sub...pay close attention to ur signs
y - (-1) = 6/11(x - (-4) ...not done yet...
y + 1 = 6/11(x + 4) <===