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2 years ago

What would I have to do here? Somebody please help me! (Look at the bottom problem not the top)

Mathematics

1 answer:

Zinaida [17]2 years ago

8 0

Alright, let's do this! If $25 is one fifth of how much the game system cost then, multiply 25 times 5. And you should get your answer.
I hope this helps.

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Write the equation of the line that is perpendicular to y = 2x - 4 that goes through

user100 [1]

Answer:

y = 2x + 13

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Which represents the reference angle for 3pi/4?

inn [45]

Answer:

Step-by-step explanation:

3pi/4 = (3 x 180) / 4 = 135 degrees

135 degrees is equivalent to (180 degrees - 135 degrees) 45 degrees

45 degrees = Pi/4

Therefore, the reference angle of 3pi/4 is Pi/4

Thus, the correct option is (c) Pi/4

8 0

3 years ago

A total of 133 million square miles of the Earth's surface are covered in water. The ratio of the area covered in water to the a

Anni [7]

Answer:

57 million square miles

Step-by-step explanation:

Let the area of water is w and area of land is l.

<u>Their ratio is:</u>

w/l = 7/3

133 / l = 7/3

Find the value of l

l = 133*3/7
l = 57 million square miles

6 0

1 year ago

He value of y varies directly with x. When y=2 2/5 , x=3/5 .

Leya [2.2K]

Answer:

I don't know sorry

it is clear that this is not online class

4 0

3 years ago

In the diagram below, the circle has a radius of 25 inches. the area of the unshaded is 500pi in^2Determine and state the degree

Dmitriy789 [7]

$72^{\circ}$

1) In this question, we are going to make use of the formula for the area of that sector, to find the central angle.

2) So, let's write it out an expression involving the area of a circle, the unshaded area, and the shaded one and then plug into that the given data:

$\begin{gathered} A=\frac{\alpha}{360^{\circ}}\times\pi r^2 \\ A_{Unshaded}+A_{shaded}=A_{Circle} \\ 500\pi+\frac{\alpha}{360}\times\pi r^2=\pi r^2 \\ \\ 500\pi+\frac{α}{360}\pi25^2=25^2\pi \\ \\ 500\pi+\frac{125\piα}{72}=625\pi \\ \\ 500\pi +\frac{125\pi α}{72}-500\pi =625\pi -500\pi \\ \\ \frac{125\pi α}{72}=125\pi \\ \\ \frac{72\times \:125\pi α}{72}=72\times \:125\pi \\ \\ \frac{125\pi α}{125\pi }=\frac{9000\pi }{125\pi } \\ \\ α=72^{\circ} \\ \\ \end{gathered}$

Thus, the centra angle of that shaded area is 72º

6 0

8 months ago